72 lines
2.2 KiB
Python
72 lines
2.2 KiB
Python
import random
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from typing import Union
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from os import path as os_path, rename as os_rename
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from PIL.Image import open as Image_open
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def getImageFile(file_name):
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img = Image_open(os_path.join(os_path.dirname(__file__), "img", file_name))
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return img
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def getKeyByValue(dictionary, value):
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for key, val in dictionary.items():
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if val == value:
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return key
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return None
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def callFunctionIfCallable(function, *args):
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if callable(function) is True:
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function(*args)
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def isEven(number):
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return number % 2 == 0
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def makeEven(number, minus:bool=False):
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if minus is True:
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return number if isEven(number) else number - 1
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return number if isEven(number) else number + 1
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def generatePercentageStringsList(start:int, end:int, step:int):
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strings = []
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for percent in range(start, end + 1, step):
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strings.append(f"{percent}%")
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return strings
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def intToPctStr(value:int):
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return f"{value}%"
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def floatToPctStr(value:float):
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return f"{int(value*100)}%"
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def strPctToInt(value:str):
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return int(value.replace("%", ""))
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def isUniqueStrings(unique_strings:Union[str, list], input_string:str, require=False):
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import re
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if isinstance(unique_strings, str):
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unique_strings = [unique_strings]
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patterns = [re.escape(s) for s in unique_strings]
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counts = [len(re.findall(pattern, input_string)) for pattern in patterns]
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if require is True:
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# If require is True, unique_strings must appear once
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return all(count == 1 for count in counts) and counts.count(1) == 2
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else:
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# If require is False, check if unique strings are used exactly once
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return all(count == 1 for count in counts)
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# path先のweightフォルダがある場合にはそのフォルダ名をweightsに変更する
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def renameWeightFolder(path):
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weight_path = os_path.join(path, "weight")
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if os_path.exists(weight_path):
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os_rename(weight_path, os_path.join(path, "weights"))
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def splitList(lst:list, split_count:int, to_shuffle:bool=False):
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if to_shuffle is True:
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random.shuffle(lst)
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split_lists = []
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for i in range(0, len(lst), split_count):
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sub_list = lst[i:i+split_count]
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split_lists.append(sub_list)
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return split_lists |